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Question
The pth, qth and rth terms of an A.P. are a, b, c respectively. Show that (q – r )a + (r – p )b + (p – q )c = 0
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Solution
Let t and d be the first term and the common difference of the A.P. respectively.
The nth term of an A.P. is given by, an = t + (n – 1) d
Therefore,
ap = t + (p – 1) d = a … (1)
aq = t + (q – 1)d = b … (2)
ar = t + (r – 1) d = c … (3)
Subtracting equation (2) from (1), we obtain
(p – 1 – q + 1) d = a – b
⇒ (p – q) d = a – b
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