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If the Sum of N Terms of an A.P. is Np + 1 2 N (N − 1) Q, Where P and Q Are Constants, Find the Common Difference.

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Question

If the sum of n terms of an A.P. is nP + \[\frac{1}{2}\] n (n − 1) Q, where P and Q are constants, find the common difference.

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Solution

\[\text { We have: } \]

\[ S_n = nP + \frac{1}{2}n(n - 1)Q\]

\[\text { For } n = 1, S_1 = P + 0 = P\]

\[\text { For } n = 2, S_2 = 2P + Q \]

\[\text { Also }, a_1 = S_1 = P, \]

\[ a_2 = S_2 - S_1 \]

\[ = 2P + Q - P = P + Q\]

\[ \therefore d = a_2 - a_1 = P + Q - P = Q \]

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Chapter 19: Arithmetic Progression - Exercise 19.4 [Page 31]

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R.D. Sharma Mathematics [English] Class 11
Chapter 19 Arithmetic Progression
Exercise 19.4 | Q 32 | Page 31

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