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Find the Sum of the Following Arithmetic Progression : 3, 9/2, 6, 15/2, ... to 25 Terms - Mathematics

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Question

Find the sum of the following arithmetic progression :

3, 9/2, 6, 15/2, ... to 25 terms

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Solution

3, 9/2, 6, 15/2 ... to 25 terms

\[\text { We have }: \]

\[ a = 3, d = \left( 9/2 - 3 \right) = 3/2\]

\[n = 25\]

\[ S_n = \frac{n}{2}\left[ 2a + (n - 1)d \right]\]

\[ = \frac{25}{2}\left[ 2 \times 3 + (25 - 1)(3/2) \right]\]

\[ = \frac{25}{2} \times 42\]

\[ = 525\]

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Chapter 19: Arithmetic Progression - Exercise 19.4 [Page 30]

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RD Sharma Mathematics [English] Class 11
Chapter 19 Arithmetic Progression
Exercise 19.4 | Q 1.3 | Page 30

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