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If 12th Term of an A.P. is −13 and the Sum of the First Four Terms is 24, What is the Sum of First 10 Terms? - Mathematics

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Question

If 12th term of an A.P. is −13 and the sum of the first four terms is 24, what is the sum of first 10 terms?

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Solution

Let a be the first term and d be the common difference.

\[a_{12} = - 13\]

\[ \Rightarrow a + \left( 12 - 1 \right)d = - 13\]

\[ \Rightarrow a + 11d = - 13 . . . (i)\]

\[\text { Also, } S_4 = 24\]

\[ \Rightarrow \frac{4}{2}\left[ 2a + (4 - 1)d \right] = 24\]

\[ \Rightarrow 2\left( 2a + 3d \right) = 24\]

\[ \Rightarrow 2a + 3d = 12 . . . (ii) \]

\[\text { From (i) and (ii), we get }: \]

\[19d = - 38\]

\[ \Rightarrow d = - 2\]

\[\text { Putting the value of d in (i), we get }: \]

\[a + 11\left( - 2 \right) = - 13\]

\[ \Rightarrow a = 9\]

\[ S_{10} = \frac{10}{2}\left[ 2 \times 9 + (10 - 1)\left( - 2 \right) \right]\]

\[ \Rightarrow S_{10} = 5\left[ 18 + 9\left( - 2 \right) \right] = 0\]

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Chapter 19: Arithmetic Progression - Exercise 19.4 [Page 31]

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RD Sharma Mathematics [English] Class 11
Chapter 19 Arithmetic Progression
Exercise 19.4 | Q 22 | Page 31

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