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Solve the following differential equation: dydxxyydydx=x2y+y

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Question

Solve the following differential equation:

`"dy"/"dx" = "x"^2"y" + "y"`

Sum
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Solution

`"dy"/"dx" = "x"^2"y" + "y"`

∴ `"dy"/"dx" = "y"("x"^2 + 1)`

∴ `1/"y" "dy" = ("x"^2 + 1)"dx"`

Integrating both sides, we get

`int 1/"y" "dy" = int ("x"^2 + 1)"dx"`

∴ `log |"y"| = "x"^3/3 + "x" + "c"`

This is the general solution.

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Chapter 6: Differential Equations - Miscellaneous exercise 2 [Page 217]

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Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 6 Differential Equations
Miscellaneous exercise 2 | Q 5.2 | Page 217

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