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Maharashtra State BoardSSC (English Medium) 10th Standard

Ratio of corresponding sides of two similar triangles is 4:7, then find the ratio of their areas = ? - Geometry Mathematics 2

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Question

Ratio of corresponding sides of two similar triangles is 4:7, then find the ratio of their areas = ?

Sum
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Solution

Let the corresponding sides of similar triangles be s1 and s2.

Let A1 and A2 be their corresponding areas.

s1 : s2 = 4 : 7        ......[Given]

∴ `"s"_1/"s"_2= 4/7`     ......(i)

by theorem of areas of similar triangles,

`"A"_1/"A"_2 = "s"_1^2/"s"_2^2`  

`"A"_1/"A"_2 = ("s"_1/"s"_2)^2`

`"A"_1/"A"_2 = (4/7)^2`    ......[From (i)]

`"A"_1/"A"_2 = 16/49`

∴ Ratio of areas of similar triangles = 16 : 49

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Chapter 1: Similarity - Q.1 (B)

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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.


Given: PQ ⊥ BC, AD ⊥ BC

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