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Question
In the given, seg BE ⊥ seg AB and seg BA ⊥ seg AD.
if BE = 6 and AD = 9 find `(A(Δ ABE))/(A(Δ BAD))`.
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Solution
`(A(Δ ABE))/(A(Δ BAD)) =(BE)/(AD)`
....[Ratio of areas of two triangles having qual base is equal to the ration of their corresponding heights.]
∴ `(A(Δ ABE))/(A(Δ BAD)) =6/9`
∴ `(A(Δ ABE))/(A(Δ BAD)) =2/3`
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