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Question
From adjoining figure, ∠ABC = 90°, ∠DCB = 90°, AB = 6, DC = 8, then `(A(ΔABC))/(A(ΔBCD))` = ?
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Solution
ΔABC and ΔBCD have same base BC.
∴ `(A(ΔABC))/(A(ΔBCD)) = (AB)/(DC)` ...[Triangles having equal base]
∴ `(A(ΔABC))/(A(ΔBCD)) = 6/8`
∴ `(A(ΔABC))/(A(ΔBCD)) = 3/4`
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