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Question
In the given figure, ∠ABC = ∠DCB = 90° AB = 6, DC = 8 then `(A(Δ ABC))/(A(Δ DCB))` = ?
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Solution
Given:
∠ABC = ∠DCB = 90°
AB = 6
DC = 8
Now,
`(A(Δ ABC))/(A(Δ DCB)) = (1/2 xx AB xx BC)/(1/2 xx DC xx BC)`
= `6/8`
= `3/4`
∴ `(A(Δ ABC))/(A(Δ DCB)) = 3/4`
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In ΔABC, B-D-C and BD = 7, BC = 20, then find the following ratio.
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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.
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Now, A(ΔPQB) = `1/2 xx square xx square`
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Therefore,
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= `square/square`
