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Question
In fig., AB ⊥ BC and DC ⊥ BC, AB = 6, DC = 4 then `("A"(Δ"ABC"))/("A"(Δ"BCD"))` = ?
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Solution
ΔABC and ΔBCD have same base BC.
∴ `"A(ΔABC)"/"A(ΔBCD)" = "AB"/"DC"` .....[Triangles having equal base]
∴ `"A(ΔABC)"/"A(ΔBCD)" = 6/4` .....[Given]
∴ `("A"(Δ"ABC"))/("A"(Δ"BCD")) = 3/2`
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