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प्रश्न
In fig., AB ⊥ BC and DC ⊥ BC, AB = 6, DC = 4 then `(A(ΔABC))/(A(ΔBCD))` = ?
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उत्तर
ΔABC and ΔBCD have same base BC.
∴ `(A(ΔABC))/(A(ΔBCD)) = (AB)/(DC)` ...[Triangles having equal base]
∴ `(A(ΔABC))/(A(ΔBCD)) = 6/4` ...[Given]
∴ `(A(ΔABC))/(A(ΔBCD)) = 3/2`
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Now, A(ΔPQB) = `1/2 xx square xx square`
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Therefore,
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= `square/square`
