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प्रश्न
In fig. BD = 8, BC = 12, B-D-C, then `(A(ΔABC))/(A(ΔABD))` = ?
पर्याय
2 : 3
3 : 2
5 : 3
3 : 4
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उत्तर
3 : 2
Explanation:
In ΔABC and ΔABD,
ΔABC and ΔABD have the same height. ...(Given)
The ratio of the areas of two triangles with equal heights is equal to the ratio of their corresponding bases.
∴ `(A(ΔABC))/(A(ΔABD)) = (BC)/(BD)`
∴ `(A(ΔABC))/(A(ΔABD)) = 12/8`
∴ `(A(ΔABC))/(A(ΔABD)) = 3/2`.
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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.
Given: PQ ⊥ BC, AD ⊥ BC
Now, A(ΔPQB) = `1/2 xx square xx square`
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Therefore,
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= `square/square`
