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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

The Ratio of the Areas of Two Triangles with Common Base is 6:5. Height of the Larger Triangle of 9 Cm, Then Find the Corresponding Height of the Smaller Triangle.

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प्रश्न

The ratio of the areas of two triangles with common base is 6:5. Height of the larger triangle of 9 cm, then find the corresponding height of the smaller triangle.

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उत्तर

Let the height of the larger triangle be h1 and that of the smaller triangle be `h_2`

The ratio of the areas of two triangles with common base is equal to the ratio of their corresponding heights.

`(A("Larger"triangle))/(A("Smaller"triangle)) = h_1/h_2`

`:. 6/5 = 9/h_2`  ...(Substituting the given values)

`∴ 6 xx h_2 = 9 xx 5`

`:. h_2 = (9 xx 5)/6 = 15/2`

`:. h_2= 7.5 cm`

The corresponding height of the smaller traingles of 7.5 cm.

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2017-2018 (March) Set A

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In the following figure RP : PK= 3 : 2, then find the value of A(ΔTRP) : A(ΔTPK).


Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.


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`(A(triangleABD))/(A(triangleABC))`


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In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.


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Therefore, 

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= `square/square`


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