A(△TRP) : A(△TPK) = 3 : 2
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प्रश्न
In the following figure RP : PK= 3 : 2, then find the value of A(ΔTRP) : A(ΔTPK).
बेरीज
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उत्तर
Ratio of the areas of two triangles with common or equal heights is equal to the ratio of their corresponding bases.
`(A(triangleTRP))/(A(triangleTPK))`
`="RP"/"PK"`
`=3/2`
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