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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

If ΔXYZ ~ ΔPQR then (XY)/(PQ) = (YZ)/(QR) = ?

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प्रश्न

If ΔXYZ ~ ΔPQR then `(XY)/(PQ) = (YZ)/(QR)` = ?

पर्याय

  • `(XZ)/(PR)`

  • `(XZ)/(PQ)`

  • `(XZ)/(QR)`

  • `(YZ)/(PQ)`

MCQ
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उत्तर

`bb((XZ)/(PR))`

Explanation:

In ΔXYZ and ΔPQR,

ΔXYZ ~ ΔPQR   ...(Given)

`(XY)/(PQ) = (YZ)/(QR) = (XZ)/(PR)`   ...[Corresponding sides of similar triangles.]

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पाठ 1: Similarity - Q.1 (A)

संबंधित प्रश्‍न

The ratio of the areas of two triangles with common base is 6:5. Height of the larger triangle of 9 cm, then find the corresponding height of the smaller triangle.


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\[\frac{BD}{CD} = \frac{AB}{AC}\]

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.


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  1. `("A"(∆"PQB"))/("A"(∆"PBC"))`
  2. `("A"(∆"PBC"))/("A"(∆"ABC"))`
  3. `("A"(∆"ABC"))/("A"(∆"ADC"))`
  4. `("A"(∆"ADC"))/("A"(∆"PQC"))`

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`(A(triangleABD))/(A(triangleABC))`


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\[\frac{A\left( ∆ ADC \right)}{A\left( ∆ ABC \right)}\] 


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if BE = 6 and AD = 9 find `(A(Δ ABE))/(A(Δ BAD))`.


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If ΔABC ∼ ΔDEF, length of side AB is 9 cm and length of side DE is 12 cm, then find the ratio of their corresponding areas.


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