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Question
In the following figure seg AB ⊥ seg BC, seg DC ⊥ seg BC. If AB = 2 and DC = 3, find `(A(triangleABC))/(A(triangleDCB))`
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Solution
In the following figure ΔABC and ΔDCB have a comman base BC.
`therefore(A(triangleABC))/(A(triangleDCB))=(AB)/(DC)`
(∵The ratio of areas of two triangles with the same base is equal to the ratio of their corresponding heights.)
`therefore(A(triangleABC))/(A(triangleDCB))=2/3`
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