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Let A = {–1, 0, 1, 2}, B = {–4, –2, 0, 2} and f, g : A → B be functions defined by f(x) = x^2 – x, x ∈ A and g(x) = 2|x – 1/2| – 1, x ∈ A. Are f and g equal? Justify your answer.

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Question

Let A = {–1, 0, 1, 2}, B = {–4, –2, 0, 2} and f, g : A → B be functions defined by f(x) = x2 – x, x ∈ A and g(x) = `2|x - 1/2| – 1`, x ∈ A. Are f and g equal?

Justify your answer. (Hint: One may note that two functions f : A → B and g : A → B such that f(a) = g(a) ∀ a ∈ A are called equal functions.)

Justify
Sum
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Solution

It is given that A = {–1, 0, 1, 2}, B = {–4, –2, 0, 2}.

Also, it is given that f, g: A → B are defined by f(x) = x2 – x, x ∈ A and `g(x) = 2|x - 1/2| - 1, x ∈ A`.

It is observed that:

When x = –1,

f(–1) = 12 – (–1)

= 1 + 1

= 2

g(–1) = `2|(-1)-1/2| - 1`

= `2(3/2) - 1`

= 3 – 1

= 2

⇒ f(–1) = g(–1)

When x = 0,

f(0) = (0)2 – 0 = 0

g(0) = `2|0 - 1/2| - 1`

= `2(1/2) - 1`

= 1 – 1

= 0

⇒ f(0) = g(0)

When x = 1,

f(1) = (1)2 – 1

= 1 – 1

= 0

g(1) = `2|1 - 1/2| - 1`

= `2(1/2) - 1`

= 1 – 1

= 0

⇒ f(1) = g(1)

When x = 2,

f(2) = (2)2 – 2

= 4 – 2

= 2

g(2) = `2|2-1/2| - 1`

= `2(3/2)-1`

= 3 – 1

= 2

⇒ f(2) = g(2)

∴ f(a) = g(a) ∀ a ∈ A

Hence, the functions f and g are equal.

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Chapter 1: Relations and Functions - Miscellaneous Exercise on Chapter 1 [Page 15]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 1 Relations and Functions
Miscellaneous Exercise on Chapter 1 | Q 5. | Page 15

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