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Let F, G, H Be Real Functions Given by F(X) = Sin X, G (X) = 2x and H (X) = Cos X. Prove that Fog = Go (Fh).

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Question

Let fgh be real functions given by f(x) = sin xg (x) = 2x and h (x) = cos x. Prove that fog = go (fh).

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Solution

We know that R[1, 1] and RR

Clearly, the range of g is a subset of the domain of f.

fo→ R

Now, (fh) (x)=(x)(x(sin x) (cos x=`1/2`sin (2x)

Domain of fh is R.

Since range of sin x is [-1,1],

≤ sin 2≤ 1

⇒ ` (-1)/2 ≤ sin x/2 ≤ 1/2`

Range of fh  = `[(-1)/2 ","1/2]`

So, (fh`[(-1)/2 ","1/2]`

Clearly, range of fh is a subset of g.

⇒ g(fh→ R

⇒ domains of fog and g(fh) are the same .

So, (fog) (x)=f (g (x)f (2xsin (2x)

and g(fh)(x= g ((fh) (x)g (sinx cos x2sin x cos sin (2x)

⇒ (fog) (x( go(fh)(x), ∈ R

Hence, fog = g(fh)

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Chapter 2: Functions - Exercise 2.3 [Page 54]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 2 Functions
Exercise 2.3 | Q 6 | Page 54

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