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Question
खालील प्रश्नासाठी उत्तराचा योग्य पर्याय निवडा.
sec2θ – tan2θ = ?
Options
0
1
2
`sqrt2`
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Solution
sec2θ – tan2θ = 1
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RELATED QUESTIONS
`sqrt((1 - sinθ)/(1 + sinθ))` = secθ - tanθ
cot θ + tan θ = cosec θ sec θ
cot2θ - tan2θ = cosec2θ - sec2θ
`1/(1 - sinθ) + 1/(1 + sinθ)` = 2sec2θ
`tanθ/(secθ + 1) = (secθ - 1)/tanθ`
जर cos θ = `24/25`, तर sin θ = ?
जर tan θ + cot θ = 2, तर tan2θ + cot2θ = ?
जर 3 sin θ = 4 cos θ, तर sec θ = ?
tan2θ – sin2θ = tan2θ × sin2θ हे सिद्ध करण्यासाठी खालील कृती पूर्ण करा.
कृती: डावी बाजू = `square`
= `square (1 - (sin^2theta)/(tan^2theta))`
= `tan^2theta (1 - square/((sin^2theta)/(cos^2theta)))`
= `tan^2theta (1 - (sin^2theta)/1 xx (cos^2theta)/square)`
= `tan^2theta (1 - square)`
= `tan^2theta xx square` .....[1 – cos2θ = sin2θ]
= उजवी बाजू
`"cot A"/(1 - tan "A") + "tan A"/(1 - cot"A")` = 1 + tan A + cot A = sec A . cosec A + 1 हे सिद्ध करा.
