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Question
जर tan θ + cot θ = 2, तर tan2θ + cot2θ = ?
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Solution
tan θ + cot θ = 2 ....[दिलेले]
∴ (tan θ + cot θ)2 = 4 .....[दोन्ही बाजूंचा वर्ग करून]
∴ tan2θ + 2tan θ.cot θ + cot2θ = 4 ......[∵ (a + b)2 = a2 + 2ab + b2]
∴ tan2θ + 2(1) + cot2θ = 4 ......[∵ tan θ ⋅ cot θ = 1]
∴ tan2θ + cot2θ = 4 – 2
∴ tan2θ + cot2θ = 2
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खालील प्रश्नासाठी उत्तराचा योग्य पर्याय निवडा.
`(1 + cot^2"A")/(1 + tan^2"A")` = ?
`(1 + sintheta)/(1 - sin theta)` = (sec θ + tan θ)2 हे सिद्ध करा.
`sec"A"/(tan "A" + cot "A")` = sin A हे सिद्ध करा.
sec2A – cosec2A = `(2sin^2"A" - 1)/(sin^2"A"*cos^2"A")` हे सिद्ध करा.
`(cot "A" + "cosec A" - 1)/(cot"A" - "cosec A" + 1) = (1 + cos "A")/"sin A"` हे सिद्ध करा.
