English

If G ( X ) = X 2 + X − 2 a N D 1 2 G O F ( X ) = 2 X 2 − 5 X + 2 is Equal to (A) 2 X − 3 (B) 2 X + 3 (C) 2 X 2 + 3 X + 1 (D) 2 X 2 − 3 X − 1

Advertisements
Advertisements

Question

If  \[g\left( x \right) = x^2 + x - 2\text{ and} \frac{1}{2} gof\left( x \right) = 2 x^2 - 5x + 2\] is equal to

Options

  • \[2 x - 3\]

  • \[2 x + 3\]

  • \[2 x^2 + 3x + 1\]

  • 2   \[x^2 - 3x - 1\]

MCQ
Advertisements

Solution

We will solve this problem by the trial-and-error method.
Let us check option (a) first. \[\text{If f}\left( x \right) = 2x - 3\] 
\[\frac{1}{2}\left( gof \right)\left( x \right) = g\left( f\left( x \right) \right)\] 
\[ = \frac{1}{2}g\left( 2x - 3 \right)\] 
\[ = \frac{1}{2}\left[ \left( 2x - 3 \right)^2 + \left( 2x - 3 \right) - 2 \right]\] 
\[ = \frac{1}{2}\left[ 4 x^2 + 9 - 12x + 2x - 3 - 2 \right]\] 
\[ = \frac{1}{2}\left[ 4 x^2 - 10x + 4 \right]\] 
\[ = 2 x^2 - 5x + 2\]

The given condition is satisfied by (a).
So, the answer is (a).

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Functions - Exercise 2.6 [Page 79]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 2 Functions
Exercise 2.6 | Q 45 | Page 79

RELATED QUESTIONS

Show that the function f : R* → R* defined by f(x) = `1/x` is one-one and onto, where R* is the set of all non-zero real numbers. Is the result true, if the domain R* is replaced by N with co-domain being same as R?


Let A = {1, 2, 3}, B = {4, 5, 6, 7} and let f = {(1, 4), (2, 5), (3, 6)} be a function from A to B. Show that f is one-one.


Let f: R → R be defined as f(x) = 10x + 7. Find the function g: R → R such that g o f = f o g = 1R.


Find the number of all onto functions from the set {1, 2, 3, ..., n} to itself.


Give an example of a function which is one-one but not onto ?


Classify the following function as injection, surjection or bijection :

 f : Z → Z, defined by f(x) = x − 5 


If f : R → R be the function defined by f(x) = 4x3 + 7, show that f is a bijection.


If A = {1, 2, 3}, show that a onto function f : A → A must be one-one.


If f : A → B and g : B → C are one-one functions, show that gof is a one-one function.


Find fog and gof  if : f(x) = c, c ∈ R, g(x) = sin `x^2`


Let f be a real function given by f (x)=`sqrt (x-2)`
Find each of the following:

(i) fof
(ii) fofof
(iii) (fofof) (38)
(iv) f2

Also, show that fof ≠ `f^2` .


Consider f : {1, 2, 3} → {a, b, c} and g : {a, b, c} → {apple, ball, cat} defined as f (1) = a, f (2) = b, f (3) = c, g (a) = apple, g (b) = ball and g (c) =  cat. Show that f, g and gof are invertible. Find f−1, g−1 and gof−1and show that (gof)−1 = f −1o g−1


Let f be a function from R to R, such that f(x) = cos (x + 2). Is f invertible? Justify your answer.


Let \[f : \left( - \frac{\pi}{2}, \frac{\pi}{2} \right) \to R\]  be a function defined by f(x) = cos [x]. Write range (f).


If f : R → R, g : R → are given by f(x) = (x + 1)2 and g(x) = x2 + 1, then write the value of fog (−3).


Write the domain of the real function f defined by f(x) = `sqrt (25 -x^2)`   [NCERT EXEMPLAR]


\[f : R \to R\] is defined by

\[f\left( x \right) = \frac{e^{x^2} - e^{- x^2}}{e^{x^2 + e^{- x^2}}} is\]

 


The function

\[f : R \to R, f\left( x \right) = x^2\]
 

Which of the following functions from

\[A = \left\{ x \in R : - 1 \leq x \leq 1 \right\}\]

 


Let  \[f\left( x \right) = x^2 and g\left( x \right) = 2^x\] Then, the solution set of the equation

\[fog \left( x \right) = gof \left( x \right)\] is 



If \[f : R \to R is given by f\left( x \right) = 3x - 5, then f^{- 1} \left( x \right)\] 

 


Let

 \[A = \left\{ x \in R : x \geq 1 \right\}\] The inverse of the function, 

\[f : A \to A\] given by

\[f\left( x \right) = 2^{x \left( x - 1 \right)} , is\]

 


If  \[f : R \to \left( - 1, 1 \right)\] is defined by

\[f\left( x \right) = \frac{- x|x|}{1 + x^2}, \text{ then } f^{- 1} \left( x \right)\] equals

 


Mark the correct alternative in the following question:
Let f : R  \[-\] \[\left\{ \frac{3}{5} \right\}\] \[\to\]  R be defined by f(x) = \[\frac{3x + 2}{5x - 3}\] Then,

 


Show that the function f: R → R defined by f(x) = `x/(x^2 + 1)`, ∀ ∈ + R , is neither one-one nor onto


Let N be the set of natural numbers and the function f: N → N be defined by f(n) = 2n + 3 ∀ n ∈ N. Then f is ______.


Let f: R → R be defined by f(x) = 3x – 4. Then f–1(x) is given by ______.


For sets A, B and C, let f: A → B, g: B → C be functions such that g o f is surjective. Then g is surjective.


Let C be the set of complex numbers. Prove that the mapping f: C → R given by f(z) = |z|, ∀ z ∈ C, is neither one-one nor onto.


Let X = {1, 2, 3}and Y = {4, 5}. Find whether the following subset of X ×Y are function from X to Y or not

k = {(1,4), (2, 5)}


Let f: R → R be the functions defined by f(x) = x3 + 5. Then f–1(x) is ______.


Let R be a relation on the set L of lines defined by l1 R l2 if l1 is perpendicular to l2, then relation R is ____________.


If f; R → R f(x) = 10x + 3 then f–1(x) is:


Consider a function f: `[0, pi/2] ->` R, given by f(x) = sinx and `g[0, pi/2] ->` R given by g(x) = cosx then f and g are


The domain of function is f(x) = `sqrt(-log_0.3(x - 1))/sqrt(x^2 + 2x + 8)` is ______.


Let S = {1, 2, 3, 4, 5, 6, 7}. Then the number of possible functions f: S `rightarrow` S such that f(m.n) = f(m).f(n) for every m, n ∈ S and m.n ∈ S is equal to ______.


ASSERTION (A): The relation f : {1, 2, 3, 4} `rightarrow` {x, y, z, p} defined by f = {(1, x), (2, y), (3, z)} is a bijective function.

REASON (R): The function f : {1, 2, 3} `rightarrow` {x, y, z, p} such that f = {(1, x), (2, y), (3, z)} is one-one.


Let A = R – {2} and B = R – {1}. If f: A `→` B is a function defined by f(x) = `(x - 1)/(x - 2)` then show that f is a one-one and an onto function.


Let f: R→Rbe defined as f (x) = `(x^2 + 1)/2`, then ______.


Many students choosing the same favourite subject resembles which type of function?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×