Advertisements
Advertisements
Question
If 3 men or 6 boys can finish a work in 20 days, how long will 4 men and 12 boys take to finish the same work?
Advertisements
Solution
3 men = 6 boys
4 men = `6/3xx4` = 8
Total boys in second case :
= 4 men + 12 boys = 8 + 12 = 20 boys
6 boys can do a piece of work in 20 days
Then let 20 boys will do the same work in x days
∴ 6 : 20 : : 20 : x ........(More boys,less days)
⇒ 6 : 20 : : x : 20 ....(By inverse proportion)
x = `(20xx6)/20`
= 6 days
∴ They will do the work in 6 days
APPEARS IN
RELATED QUESTIONS
12 pipes, all of the same size, fill a tank in 42 minutes. How long will it take to fill the same tank, if 21 pipes of the same size are used?
If 56 workers can build a wall in 180 hours, how many workers will be required to do the same work in 70 hours?
If 15 men can complete a piece of work in 30 days, in how many days will 18 men complete it?
90 men can complete a work in 24 days working 8 hours a day. How many men are required to complete the same work in 18 days working `7 1/2` hours a day?
A can do a piece of work in 10 days and B in 15 days. How long will they take together to finish it?
A can do a work in 15 days and B in 20 days. If they together work on it for 4 days; what fraction of the work will be left?
A can do a piece of work in 24 days, A and B can do it in 16 days and A, B, and C in `10 2/3` days. In how many days can A and C do it working together?
A can finish a piece of work in 15 days and B can do it in 10 days. They worked together for 2 days and then B goes away. In how many days will A finish the remaining work?
A and B can do a work in 8 days; B and C in 12 days, and A and C in 16 days. In what time could they do it, all working together?
Two pipes P and Q would fill an empty cistern in 24 minutes and 32 minutes respectively. Both the pipes being opened together, find when the first pipe must be turned off so that the empty cistern maybe just filled in 16 minutes.
