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How Many Different Numbers, Greater than 50000 Can Be Formed with the Digits 0, 1, 1, 5, 9. - Mathematics

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Question

How many different numbers, greater than 50000 can be formed with the digits 0, 1, 1, 5, 9.

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Solution

Numbers greater than 50000 can either have 5 or 9 in the first place and will consist of 5 digits.
Number of arrangements having 5 as the first digit =\[\frac{4!}{2!}\]

Number of arrangement having 9 as the first digit =\[\frac{4!}{2!}\]

∴ Required arrangements =\[\frac{4!}{2!}\]+\[\frac{4!}{2!}\]=24

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Factorial N (N!) Permutations and Combinations
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Chapter 16: Permutations - Exercise 16.5 [Page 43]

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RD Sharma Mathematics [English] Class 11
Chapter 16 Permutations
Exercise 16.5 | Q 11 | Page 43

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