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There Are Two Works Each of 3 Volumes and Two Works Each of 2 Volumes; in How Many Ways Can the 10 Books Be Placed on a Shelf So that the Volumes of the Same Work Are Not Separated?

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Question

There are two works each of 3 volumes and two works each of 2 volumes; In how many ways can the 10 books be placed on a shelf so that the volumes of the same work are not separated?

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Solution

There are 4 different types of works.
∴ Number of arrangements of these 4 works, taken 4 at a time = 4!
Of these 4 works, two of the works with 3 volumes each can be arranged in 3! ways each and two of the works with 2 volumes each can be arranged in 2! ways.
Total number of arrangements  = 4! x (3! x 3!) x (2! x 2!) = 3456

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Factorial N (N!) Permutations and Combinations
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Chapter 16: Permutations - Exercise 16.3 [Page 29]

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R.D. Sharma Mathematics [English] Class 11
Chapter 16 Permutations
Exercise 16.3 | Q 23 | Page 29

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