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How Many Three-digit Numbers Are There, with Distinct Digits, with Each Digit Odd?

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Question

How many three-digit numbers are there, with distinct digits, with each digit odd?

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Solution

The odd digits are 1, 3, 5, 7 and 9.

Required number of ways = Number of arrangements of five digits ( 1, 3, 5, 7 and 9), taken three at a time = 5P3

\[= \frac{5!}{(5 - 3)!}\]
\[ = \frac{5!}{2!}\]
\[ = \frac{5 \times 4 \times 3 \times 2!}{2!}\]
\[ = 5 \times 4 \times 3\]
\[ = 60\]
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Factorial N (N!) Permutations and Combinations
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Chapter 16: Permutations - Exercise 16.3 [Page 28]

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R.D. Sharma Mathematics [English] Class 11
Chapter 16 Permutations
Exercise 16.3 | Q 20 | Page 28

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