English

Find the total number of ways in which six ‘+’ and four ‘−’ signs can be arranged in a line such that no two ‘−’ signs occur together.

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Question

Find the total number of ways in which six ‘+’ and four ‘−’ signs can be arranged in a line such that no two ‘−’ signs occur together.

Sum
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Solution

We have 6 ‘+’ signs:

This creates 7 gaps (slots) where ‘−’ signs can be placed:

  • One before the first ‘+’

  • Five between each pair of ‘+’

  • One after the last ‘+’

(7 slots in total)

We have 4 ‘−’ signs, and no two can be together.
That means each ‘−’ must go into a different slot.

Choose 4 slots out of 7 to place the ‘−’ signs.

The number of ways = `((7),(4)) = 35`

The total number of ways = 35.

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Factorial N (N!) Permutations and Combinations
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Chapter 16: Permutations - Exercise 16.5 [Page 43]

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R.D. Sharma Mathematics [English] Class 11
Chapter 16 Permutations
Exercise 16.5 | Q 26 | Page 43

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