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In How Many Ways Can Five Children Stand in a Queue?

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Question

In how many ways can five children stand in a queue?

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Solution

Required number of ways = Number of arrangements of all the children = 5P5 = 5!
We know:
nPn = n!
∴ 5P5  = 5! = 120  

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Factorial N (N!) Permutations and Combinations
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Chapter 16: Permutations - Exercise 16.3 [Page 28]

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R.D. Sharma Mathematics [English] Class 11
Chapter 16 Permutations
Exercise 16.3 | Q 15 | Page 28

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