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How Many 3-digit Numbers Can Be Formed by Using the Digits 1 to 9 If No Digit is Repeated?

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Question

How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?

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Solution

Total number of arrangements of 9 digits, taken 3 at a time = 9P3
∴ Total 3-digit numbers that can be formed by using the digits 1 to 9, if no digit is repeated = 9P3 = `9xx8xx7=504`

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Factorial N (N!) Permutations and Combinations
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Chapter 16: Permutations - Exercise 16.3 [Page 29]

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R.D. Sharma Mathematics [English] Class 11
Chapter 16 Permutations
Exercise 16.3 | Q 29 | Page 29

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