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How can three resistors of resistances 2 Ω, 3 Ω and 6 Ω be connected to give a total resistance of 4 Ω ? - Science

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Question

How can three resistors of resistances 2 Ω, 3 Ω and 6 Ω be connected to give a total resistance of 4 Ω ?

Numerical
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Solution

There are three resistors of resistances: 2 Ω, 3 Ω, and 6 Ω, respectively.

The following circuit diagram shows the connection of the three resistors.

Here, 6 Ω and 3 Ω resistors are connected in parallel.

Therefore, their equivalent resistance will be given by

`1/(1/6+1/3)`

 = `(6xx3)/(6+3)`

= 2 Ω

This equivalent resistor of resistance 2 Ω is connected to a 2 Ω resistor in series.

Therefore, the equivalent resistance of the circuit = 2 Ω + 2 Ω = 4 Ω

Hence the total resistance of the circuit is 4 Ω.

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Chapter 12: Electricity - Intext Questions [Page 216]

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NCERT Science [English] Class 10
Chapter 12 Electricity
Intext Questions | Q 4 | Page 216

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