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प्रश्न
How can three resistors of resistances 2 Ω, 3 Ω and 6 Ω be connected to give a total resistance of 4 Ω ?
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उत्तर
There are three resistors of resistances: 2 Ω, 3 Ω, and 6 Ω, respectively.
The following circuit diagram shows the connection of the three resistors.
Here, 6 Ω and 3 Ω resistors are connected in parallel.
Therefore, their equivalent resistance will be given by
`1/(1/6+1/3)`
= `(6xx3)/(6+3)`
= 2 Ω
This equivalent resistor of resistance 2 Ω is connected to a 2 Ω resistor in series.
Therefore, the equivalent resistance of the circuit = 2 Ω + 2 Ω = 4 Ω
Hence the total resistance of the circuit is 4 Ω.
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संबंधित प्रश्न
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