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Find the differential equation by eliminating arbitrary constants from the relation y = (c1 + c2x)ex

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Question

Find the differential equation by eliminating arbitrary constants from the relation y = (c1 + c2x)ex 

Sum
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Solution

y = (c1 + c2x)ex       ......(i)

Here, c1 and c2 are arbitrary constants.

Differentiating w.r.t. x, we get

`("d"y)/("d"x)` = (c1 + c2x)ex + c2ex

∴ `("d"y)/("d"x)` = y + c2ex   ......(ii) .......[From(i)]

Again, differentiating w.r.t. x, we get

`("d"^2y)/("d"x^2) = ("d"y)/("d"x) + "c"_2"e"^x`

∴ c2ex = `("d"^2y)/("d"x^2) - ("d"y)/("d"x)`   .....(iii)

Substituting (iii) in (ii), we get

`("d"y)/("d"x) = y + ("d"^2y)/("d"x^2) -  ("d"y)/("d"x)`

∴ `("d"^2y)/("d"x^2) - 2 ("d"y)/("d"x) + y` = 0

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Chapter 2.6: Differential Equations - Attempt the following questions II

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SCERT Maharashtra Mathematics and Statistics (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 2.6 Differential Equations
Attempt the following questions II | Q 8

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