Advertisements
Advertisements
Question
Find the circuit in the three resistors shown in the figure.
Advertisements
Solution
Applying KVL in loop 1, we get:-
\[2 + \left( i_1 - i_2 \right) \times 1 - 2 = 0\]
\[ \Rightarrow i_1 = i_2\]
Applying KVL in loop 2, we get:-
\[2 + \left( i_2 - i_3 \right) \times 1 - 2 - \left( i_1 - i_2 \right) \times 1 = 0\]
\[ \Rightarrow i_2 - i_3 - i_1 + i_2 = 0\]
\[ i_1 = i_2 \]
\[ \Rightarrow i_2 - i_3 - i_2 + i_2 = 0\]
\[ \Rightarrow i_2 = i_3\]
Applying KVL in loop 3, we get:-
\[2 + i_3 - 2 - \left( i_2 - i_3 \right) = 0\]
\[ \Rightarrow i_3 = 0\]
\[ i_1 = i_2 = i_3 \]
\[ \therefore i_1 = i_2 = i_3 = 0\]
APPEARS IN
RELATED QUESTIONS
Kirchhoff's junction law is equivalent to .............................
(a) conservation of energy.
(b) conservation of charge
(c) conservation of electric potential
(d) conservation of electric flux
Determine the equivalent resistance of networks shown in Fig.
Determine the equivalent resistance of networks shown in Fig.
In the given circuit, assuming point A to be at zero potential, use Kirchhoff’s rules to determine the potential at point B.
Consider the potentiometer circuit as arranged in the figure. The potentiometer wire is 600 cm long. (a) At what distance from the point A should the jockey touch the wire to get zero deflection in the galvanometer? (b) If the jockey touches the wire at a distance of 560 cm from A, what will be the current in the galvanometer?
In the circuit shown in the figure below, E1 and E2 are two cells having emfs 2 V and 3 V respectively, and negligible internal resistance. Applying Kirchhoff’s laws of electrical networks, find the values of currents l1 and I2.
Twelve wires each having a resistance of 3 Ω are connected to form a cubical network. A battery of 10 V and negligible internal resistance is connected across the diagonally opposite corners of this network. Determine its equivalent resistance and the current along each edge of the cube.
A potentiometer wire has a length of 4 m and resistance of 20 Ω. It is connected in series with resistance of 2980 Ω and a cell of emf 4 V. Calculate the potential along the wire.
In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63 cm, what is the emf of the second cell?
Figure shows current in a part of an electrical circuit. Then current I is ______.
Kirchhoff s second law is based on the law of conservation of ______
In a meter bridge the point D is a neutral point (Figure).
- The meter bridge can have no other neutral point for this set of resistances.
- When the jockey contacts a point on meter wire left of D, current flows to B from the wire.
- When the jockey contacts a point on the meter wire to the right of D, current flows from B to the wire through galvanometer.
- When R is increased, the neutral point shifts to left.
What are the advantages of the null-point method in a Wheatstone bridge? What additional measurements would be required to calculate `R_(unknown)` by any other method?
What is the advantage of using thick metallic strips to join wires in a potentiometer?
Why are alloys used for making standard resistance coils?
The circuit in figure shows two cells connected in opposition to each other. Cell E1 is of emf 6V and internal resistance 2Ω; the cell E2 is of emf 4V and internal resistance 8Ω. Find the potential difference between the points A and B.
Two cells of voltage 10V and 2V and internal resistances 10Ω and 5Ω respectively, are connected in parallel with the positive end of 10V battery connected to negative pole of 2V battery (Figure). Find the effective voltage and effective resistance of the combination.
A 6-volt battery is connected to the terminals of a three-metre-long wire of uniform thickness and resistance of 100 ohms. The difference of potential between two points on the wire separated by a distance of 50 cm will be ______.
