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Tamil Nadu Board of Secondary EducationHSC Science Class 12

A potentiometer wire has a length of 4 m and resistance of 20 Ω. It is connected in series with resistance of 2980 Ω and a cell of emf 4 V. Calculate the potential along the wire.

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Question

A potentiometer wire has a length of 4 m and resistance of 20 Ω. It is connected in series with resistance of 2980 Ω and a cell of emf 4 V. Calculate the potential along the wire.

Numerical
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Solution

Given data:

l = 4m of R = 20Ω

In series with R’ = 2980Ω

E = 4 V

Since 20 is in series with 2980

Reff = 20 + 2980 = 3000

current I = `"V"/"R"_"eff" = 4/3000 = 1.3 xx 10^-3 "A"`

I = `1.3 xx 10^-3`A

Potential along the wire of 4 m length is,

`"V"/"l" - "IR"/"l" = (1.3 xx 10^-3 xx 20)/4`

`= (26 xx 10^-3)/4`

= 6.5 × 10-3 Vm-1

`"V"/"l" = 6.5 xx 10^-2 "Vm"^-1`

Potential = `0.65 xx 10^-2 "Vm"^-1`

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Chapter 2: Current Electricity - Evaluation [Page 122]

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Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 2 Current Electricity
Evaluation | Q IV. 10. | Page 122

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