Advertisements
Advertisements
प्रश्न
A potentiometer wire has a length of 4 m and resistance of 20 Ω. It is connected in series with resistance of 2980 Ω and a cell of emf 4 V. Calculate the potential along the wire.
Advertisements
उत्तर
Given data:
l = 4m of R = 20Ω
In series with R’ = 2980Ω
E = 4 V
Since 20 is in series with 2980
Reff = 20 + 2980 = 3000
current I = `"V"/"R"_"eff" = 4/3000 = 1.3 xx 10^-3 "A"`
I = `1.3 xx 10^-3`A
Potential along the wire of 4 m length is,
`"V"/"l" - "IR"/"l" = (1.3 xx 10^-3 xx 20)/4`
`= (26 xx 10^-3)/4`
= 6.5 × 10-3 Vm-1
`"V"/"l" = 6.5 xx 10^-2 "Vm"^-1`
Potential = `0.65 xx 10^-2 "Vm"^-1`
APPEARS IN
संबंधित प्रश्न
State Kirchhoff's rules and explain on what basis they are justified.
Consider the circuit shown in the figure. Find (a) the current in the circuit (b) the potential drop across the 5 Ω resistor (c) the potential drop across the 10 Ω resistor (d) Answer the parts (a), (b) and (c) with reference to the figure.
In the circuit shown in the figure below, E1 and E2 are two cells having emfs 2 V and 3 V respectively, and negligible internal resistance. Applying Kirchhoff’s laws of electrical networks, find the values of currents l1 and I2.
Kirchhoff’s second law is a consequence of law of conservation of ______.
The figure below shows current in a part of electric circuit. The current I is ______.
A 6-volt battery is connected to the terminals of a three-metre-long wire of uniform thickness and resistance of 100 ohms. The difference of potential between two points on the wire separated by a distance of 50 cm will be ______.
In the circuit shown in Figure below, E1 and E2 are batteries having emfs of 25V and 26V. They have an internal resistance of 1 Ω and 5 Ω respectively. Applying Kirchhoff’s laws of electrical networks, calculate the currents I1 and I2.
The figure below shows two batteries, E1 and E2, having emfs of 18V and 10V and internal resistances of 1 Ω and 2 Ω, respectively. W1, W2 and W3 are uniform metallic wires AC, FD and BE having resistances of 8 Ω, 6 Ω and 10 Ω respectively. B and E are midpoints of the wires W1 and W2. Using Kirchhoff's laws of electrical circuits, calculate the current flowing in the wire W3:
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is:
