Advertisements
Advertisements
Question
Diagram is given below shows velocity – time graph of car P and Q, starting from the same place and in the same direction. Calculate the Acceleration of car Q between 2 s – 5 s.

Advertisements
Solution

Acceleration of car Q between 2 s − 5 s = +Slope of v-t graph (CD) for car Q
= `"DE"/"CE"=25/(5-2)=25/3` = 8.33 ms−2
APPEARS IN
RELATED QUESTIONS
Define acceleration. State its unit.
A bullet initially moving with a velocity 20 m/s strikes a target and comes to rest after penetrating a distance 10 cm into the target. Calculate the retardation caused by the target.
Draw velocity – time graph for the following situation:
When a body is moving with variable velocity, but uniform retardation.
From the diagram given below, calculate acceleration.

State if the following situation is possible:
A body moving with constant acceleration but with Zero velocity.
Interpret the following graph:
When a body starts from rest, the acceleration of the body after 2 seconds in ______ of its displacement.
What is meant by negative acceleration?
When an object undergoes acceleration ______.
An object can be moving with uniform speed but with variable acceleration.
