Advertisements
Advertisements
Question
An object of mass 16 kg is moving with an acceleration of 3 m/s2. Calculate the applied force. If the same force is applied to an object of mass 24 kg, how much will be the acceleration?
Advertisements
Solution
Given: m1 = 16 kg, a1 = 3 m/s2, m2 = 24 kg
Find: a2 = ?, F = ?
Applied force, F = m1a1 = 16 kg × 3 m/s2 = 48 N
∴ F = m2a2
∴ Acceleration, `"a"_2 = "F"/"m"_2`
`= (48 "N")/(24 "kg")`
= 2 m/s2
APPEARS IN
RELATED QUESTIONS
The velocity-time graph for a uniformly retarded body is a straight line inclined to the time axis with an obtuse angle. How is retardation calculated from the velocity-time graph?
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.

Which part of graph shows motion with uniform
(a) velocity (b) acceleration (c) retardation ?
A vehicle is accelerating on a straight road. Its velocity at any instant is 30 km/h. After 2 s, it is 33.6 km/h, and after further 2 s, it is 37.2 km/h. Find the acceleration of the vehicle in m s-2. Is the acceleration uniform?
Explain the following concept in your own words with everyday examples:
Acceleration
A racing car is moving with a velocity of 50 m/s. On
applying brakes, it is uniformly retarded and comes to rest in 20 seconds. Calculate its acceleration.
From the diagram given below, calculate deceleration.

From the velocity – time graph given below, calculate deceleration in region BC.

Define acceleration.
The speed of a car increases from 10 km/h to 64 km/h in 10 seconds. What will be its acceleration?
Interpret the following graph:
What happens to the stepwise increasing speed-time graph when the size of each step is made very small?
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
The Deceleration.
Figure represents graphically the velocity of a car moving along a straight road over a period of 100 hours.
Calculate the acceleration along AB and the retardation along BC.
The rate of change of velocity is ______.
Negative acceleration is called ______.
Exercise Problem.
A racing car has a uniform acceleration of 4 ms–2. What distance it covers in 10 s after the start?
The Unit of acceleration is ______.
It is possible to have objects moving with uniform speed but variable acceleration.
Assertion: When a body is subjected to a uniform acceleration, it is always moving in a straight line.
Reason: Motion may be straight-line motion or circular motion.
