Advertisements
Advertisements
Question
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
Distance travelled
Advertisements
Solution
Distance travelled= area under speed time graph = `1/2`x30x30 =450 m.
APPEARS IN
RELATED QUESTIONS
Give one example of the following motion:
Uniform retardation
The velocity-time graph for a uniformly retarded body is a straight line inclined to the time axis with an obtuse angle. How is retardation calculated from the velocity-time graph?
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
(a) Is the magnitude of acceleration higher or lower than that of retardation ? Give a reason .
(b) Compare the magnitude of acceleration and retardation .
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
Which part of graph shows motion with uniform
(a) velocity (b) acceleration (c) retardation ?
If a body is moving with a constant velocity its acceleration is ______.
When is the acceleration due to gravity positive?
Can you use the relation [B1]?
A body has an acceleration of -3.5 ms-2. What is its retardation?
Sketch the shape of the velocity-time graph for a body moving with:
Uniform acceleration.
Assertion: When a body is subjected to a uniform acceleration, it is always moving in a straight line.
Reason: Motion may be straight-line motion or circular motion.
