Advertisements
Advertisements
प्रश्न
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
Distance travelled
Advertisements
उत्तर

Distance travelled= area under speed time graph = `1/2`x30x30 =450 m.
APPEARS IN
संबंधित प्रश्न
Give one example of the following motion:
Uniform retardation
Define the term acceleration due to gravity. State its average value.
A ball is rolling from A to D on a flat and smooth surface. Its speed is 2 cm/s. On reaching B, it was pushed continuously up to C. On reaching D from C, its speed had become 4 cm/s. It took 2 seconds for it to go from B to C. What is the acceleration of the ball as it goes from B to C?

A cyclist driving at 36 kmh−1 stops his motion in 2 s, by the application of brakes. Calculate
- retardation
- distance covered during the application of brakes.
Write the SI unit of acceleration and retardation.
Interpret the following graph:
A quantity has a value of 16ms-2. It is the ______.
A car is being driven at a speed of 20ms-1 when brakes are applied to bring it to rest in 5 s. The deceleration produced in this case will be ______.
The value of acceleration for a body at rest is ______.
Assertion: A negative acceleration of a body can be associated with speeding up of the body.
Reason: Increase in the speed of a moving body is independent of its direction of motion.
