Advertisements
Advertisements
प्रश्न
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
Distance travelled
Advertisements
उत्तर

Distance travelled= area under speed time graph = `1/2`x30x30 =450 m.
APPEARS IN
संबंधित प्रश्न
The velocity-time graph for a uniformly retarded body is a straight line inclined to the time axis with an obtuse angle. How is retardation calculated from the velocity-time graph?
A body falls freely from a certain height. Show graphically the relation between the distance fallen and square of time. How will you determine g from this graph?
If a body is moving with a constant velocity its acceleration is ______.
A body falls towards the earth. Does it have positive or negative acceleration?
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
The acceleration.
The acceleration of the body that moves with a uniform velocity will be ______.
Acceleration is defined as the rate of change of ______.
A car is being driven at a speed of 20ms-1 when brakes are applied to bring it to rest in 5 s. The deceleration produced in this case will be ______.
Assertion: A negative acceleration of a body can be associated with speeding up of the body.
Reason: Increase in the speed of a moving body is independent of its direction of motion.
What is the difference between uniform acceleration and non–uniform acceleration?
