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प्रश्न
A body falls freely from a certain height. Show graphically the relation between the distance fallen and square of time. How will you determine g from this graph?
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उत्तर
The value of acceleration due to gravity (g) can be obtained by doubling the slope of the S - t2 graph for a freely falling body.
संबंधित प्रश्न
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
Which part of graph shows motion with uniform
(a) velocity (b) acceleration (c) retardation ?
A car travels with uniform velocity of 25 m s-1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find:
- The distance which the car travels before the brakes are applied,
- Retardation and
- The distance travelled by car after applying the brakes.
When is the acceleration due to gravity negative?
Draw velocity – time graph for the following situation:
When a body is moving with variable velocity, but uniform retardation.
From the diagram given below, calculate acceleration.
From the velocity – time graph given below, calculate deceleration in region BC.
The acceleration of a moving body is constant in magnitude and direction. Must the path of the body be a straight line?
If not, given an example.
The distance covered by a body is directly proportional to the square of the time elapsed. What can you say about its acceleration?
Assertion: The accelerated motion of an object may be due to change in magnitude of velocity or direction or both of them.
Reason: Acceleration can be produced only by change in magnitude of the velocity. It does not depend the direction.
A quantity has a value of 16ms-2. It is the ______.
