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Question
A body moves along a straight track. Half of the distance it covers with a velocity of 40 ms-1 and the remaining half with a velocity of 60 ms-1. What is the average velocity for the whole journey?
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Solution
Let total distance be S.
Body covers distance S/2 with speed 40 ms-1 then the time taken by him to cover this distance would be T1 =S/2 X 40.
Again body covers the rest of the distance S/2 with speed 60 ms-1 then the time taken by him to cover this distance would be T2 =S/2 X 60.
So total time taken by the body to cover the distance S is T = T1 + T2.
Total time T= S/2 (1/40 +1/60) = s(40+60)/2 X 40 X 60 = s/48.
And average speed = S/T = 48 ms-1.
So average speed is 48 ms-1.
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