Advertisements
Advertisements
Question
A body is moving vertically upwards. Its velocity changes at a constant rate from 50 m s−1 to 20 m s−1 in 3 s. What is its acceleration?
Advertisements
Solution
Here, final velocity = 20 m/s
Initial velocity = 50 m/s
Time taken = 3 s
Acceleration = `("Final Velocity" - "Initial Velocity")/"time"`
= `(20 - 50)/3` m/s−2
= −10 m/s−2
The negative sign here indicates that the velocity decreases with time, so retardation is 10 m/s−2.
APPEARS IN
RELATED QUESTIONS
The unit of retardation is ____________
The change in velocity of a motorbike is 54 kmh−1 in one minute. Calculate its acceleration in (a) ms−2 (b) kmh−2.
From the diagram given below, calculate deceleration.
A cyclist driving at 36 kmh−1 stops his motion in 2 s, by the application of brakes. Calculate
- retardation
- distance covered during the application of brakes.
The initial velocity of a car is 10 ms-1. It moves with an acceleration of 2 ms-2. What will be its speed after 10 seconds?
Sketch the shape of the velocity-time graph for a body moving with:
Uniform acceleration.
The rate of change of velocity is ______.
A bus can accelerate with an acceleration of 1 m/s2 . Find the minimum time for the bus to attain the speed of 100 km/s from 50 km /s.
A bus accelerating with 4ms-2 changes its speed from 60ms_1 to a certain value in 5s. The final speed is ______.
When a body is said to be in
- uniform acceleration
- non–uniform acceleration?
