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(C) Fill in the Blanks in the Table: P (A) P (B) P (A ∩ B) P(A∪ B) 0.5 0.35 ..... 0.7 - Mathematics

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Question

Fill in the blank in the table:

P (A) P (B) P (A ∩ B) P(A∪ B)
0.5 0.35 ..... 0.7
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Solution

Given: \[P\left( A \right) = \frac{1}{3}, P\left( B \right) = \frac{1}{5} \text{ and }  P\left( A \cap B \right) = \frac{1}{15}\]
Given:
P (A) = 0.5, P(B) = 0.35 and P (A ∪ B) = 0.7
By addition theorem, we have:
P (A ∪ B) = P(A) + P (B) - P (A ∩ B)
          0.7  = 0.5 + 0.35 - P (A ∩ B)
  P (A ∩ B) = 0.5 + 0.35 -  0.7
                = 0.85 -  0.7 = 0.15

 
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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
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Chapter 33: Probability - Exercise 33.4 [Page 67]

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RD Sharma Mathematics [English] Class 11
Chapter 33 Probability
Exercise 33.4 | Q 1.3 | Page 67

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