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Question
In a simultaneous throw of a pair of dice, find the probability of getting a doublet
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Solution
We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36Let E2 = event of getting a doublet
Then E2 = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}
i.e. n (E2) = 6
\[\therefore P\left( E_2 \right) = \frac{n\left( E_2 \right)}{n\left( S \right)} = \frac{6}{36} = \frac{1}{6}\]
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