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Question
In a simultaneous throw of a pair of dice, find the probability of getting a total of 9 or 11
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Solution
We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36
Let E15 = event of getting a total of 9 or 11
Then E15 = {(3, 6), (4, 5), (5, 4) , (5, 6), (6, 3), (6, 5) }
i.e. n (E15) = 6
\[\therefore P\left( E_{15} \right) = \frac{n\left( E_{15} \right)}{n\left( S \right)} = \frac{6}{36} = \frac{1}{6}\]
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