Question

A box contains 10 good articles and 6 with defects. One item is drawn at random. The probability that it is either good or has a defect is

Options

•  64/64

•  49/64

•  40/64

• 24/64

   

Answer 1

 \[\frac{64}{64}\]

Let A be the event of drawing one good article whereas B be the event of drawing one defected article.

Here,

\[P\left( A \right) = \frac{10}{10 + 6} = \frac{10}{16} \text{ and }  P\left( B \right) = \frac{6}{10 + 6} = \frac{6}{16}\]

The events A and B are mutually exclusive. Thus, the required probability is \[P\left( A \cup B \right) = P\left( A \right) + P\left( B \right)\]

\[\Rightarrow P\left( A \cup B \right) = \frac{10}{16} + \frac{6}{16} = \frac{16}{16} = 1\]