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One of the Two Events Must Occur. If the Chance of One is 2/3 of the Other, Then Odds in Favour of the Other Are (A) 1 : 3 (B) 3 : 1 (C) 2 : 3 (D) 3 : 2 - Mathematics

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Question

One of the two events must occur. If the chance of one is 2/3 of the other, then odds in favour of the other are

Options

  •  1 : 3

  • 3 : 1

  •  2 : 3

  •  3 : 2

     
MCQ
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Solution

 3 : 2

Let P(B) = x
Then, P(A) = \[\frac{2x}{3}\]

P(A) + P(B) = \[x + \frac{2x}{3} = \frac{5x}{3}\]

\[\Rightarrow \frac{5x}{3} = 1\]
   (∵ They are exhaustive events)

\[\Rightarrow x = \frac{3}{5}\]

Now,

\[P(A) = \frac{2}{5} and P\left( B \right) = \frac{3}{5}\]
 
∴ Odd in favour of B = \[\frac{3/5}{1 - 3/5} = \frac{3}{2} = 3: 2\]
 
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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
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Chapter 33: Probability - Exercise 33.6 [Page 72]

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RD Sharma Mathematics [English] Class 11
Chapter 33 Probability
Exercise 33.6 | Q 17 | Page 72

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