Question

One of the two events must occur. If the chance of one is 2/3 of the other, then odds in favour of the other are

पर्याय

•  1 : 3

• 3 : 1

•  2 : 3

•  3 : 2

   

Answer 1

 3 : 2

Let P(B) = x
Then, P(A) = \[\frac{2x}{3}\]

P(A) + P(B) = \[x + \frac{2x}{3} = \frac{5x}{3}\]

\[\Rightarrow \frac{5x}{3} = 1\]

   (∵ They are exhaustive events)

\[\Rightarrow x = \frac{3}{5}\]

Now,

\[P(A) = \frac{2}{5} and P\left( B \right) = \frac{3}{5}\]

 

∴ Odd in favour of B = \[\frac{3/5}{1 - 3/5} = \frac{3}{2} = 3: 2\]