मराठी

In a class of 60 students, 30 opted for NCC, 32 opted for NSS and 24 opted for both NCC and NSS. If one of these students is selected at random, - Mathematics

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प्रश्न

In a class of 60 students, 30 opted for NCC, 32 opted for NSS and 24 opted for both NCC and NSS. If one of these students is selected at random, find the probability that

  1. The student opted for NCC or NSS.
  2. The student has opted neither NCC nor NSS.
  3. The student has opted NSS but not NCC.
बेरीज
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उत्तर

Let A and B represent the events of opted NCC and NSS respectively.

Total number of students = 60

Number of students who opted for NCC = 30

Probability of being selected for NCC P(A) = `30/60 = 1/2`

Number of students who opted for N.S.S. = 32

∴ Probability of being selected for N.S.S. P(B) = `32/60`

Number of people who opted for NCC and NSS = 24

Probability of opted for NCC and NSS = `24/60`

(i) Probability of being selected for NCC and NSS P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

= `30/60 + 32/60 - 24/60`

= `38/60`

= `19/30`

(ii) The probability of not selecting either NCC or NSS

P(A’ ∩ B’) = P[(A ∪ B)’]

= 1 – P(A ∪ B)

= `1 - 19/30`

= `11/30`

(iii) The student has opted for NSS but not NCC

Its probability = P(A’ ∩ B) = P(B) – P(A ∩ B)

= `32/60 - 24/60`

= `8/60`

= `2/15`

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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 16: Probability - Exercise 16.3 [पृष्ठ ४०६]

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एनसीईआरटी Mathematics [English] Class 11
पाठ 16 Probability
Exercise 16.3 | Q 21 | पृष्ठ ४०६

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