Question

In a simultaneous throw of a pair of dice, find the probability of getting a doublet of prime numbers

Answer 1

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

  Let E₃ = event of getting a doublet of prime numbers
Then E₃ = {(2, 2), (3, 3), (5, 5)}
        i.e. n (E₃) = 3

\[\therefore P\left( E_3 \right) = \frac{n\left( E_3 \right)}{n\left( S \right)} = \frac{3}{36} = \frac{1}{12}\]