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In a Simultaneous Throw of a Pair of Dice, Find the Probability of Getting:(Iii) a Doublet of Prime Numbers

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प्रश्न

In a simultaneous throw of a pair of dice, find the probability of getting a doublet of prime numbers

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उत्तर

We know that in a single throw of two dices, the total number of possible outcomes is (6 × 6) = 36.
Let S be the sample space.
Then n(S) = 36

  Let E3 = event of getting a doublet of prime numbers
Then E3 = {(2, 2), (3, 3), (5, 5)}
        i.e. n (E3) = 3

\[\therefore P\left( E_3 \right) = \frac{n\left( E_3 \right)}{n\left( S \right)} = \frac{3}{36} = \frac{1}{12}\]

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Concept of Probability - Probability of 'Not', 'And' and 'Or' Events
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 33: Probability - Exercise 33.3 [पृष्ठ ४५]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 33 Probability
Exercise 33.3 | Q 2.03 | पृष्ठ ४५

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